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Maths / Triangles / Angle Sum Property of a Triangle
QUESTION
 

A tringle ABC is right angled at A. AL is drawn perpendicular to BC.prove that large angle BAL=angle ACB

EXPLANATION
Explain TypeExplanation Content
Text

Solution in Delta ABL , we have

angle BAL+angle ALB +angle B=180^0

angle BAL+90^0+angle B=180^0                                                therefore AL triangle BC:::::::therefore angel ALB=90^0

angle BAL+angle B=90^0

angle BAL=90^0-angle B

Delta ABC, we have

angle A+angle B+angle C=180^0

90^0+angle B+angle C=180^0

angle B+angle C=180^0-90^0

angle B+angle C=90^0

angle C=90^0-angle B

angle ACB=90^0-angle B          ......(II)     FIG.9.6

From (i) and (ii), we  get

angle BAL=angle ACB

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